Force Acceleration Calculation

Force Acceleration Calculation

Can you help me with this physics homework? Calculate the force acting on a 5 kg object when it is subjected to a horizontal force of 20 N. Thank you!

Academic Artisan

APA

Answer

Force Acceleration Calculation : Let’s solve this using Newton’s Second Law of Motion:

$$F=ma$$

Where:

• $F$ is the force applied (20 N),
• $m$ is the mass of the object (5 kg),
• $a$ is the acceleration, which we need to find.

First, let’s rearrange the equation to solve for acceleration:

a=Fm=205=4 m/s2a = \frac{F}{m} = \frac{20}{5} = 4 \, \text{m/s}^2a=mF​=520​=4m/s2

So, the acceleration of the object is 4 m/s24 \, \text{m/s}^24m/s2.

Let’s solve this using Newton’s Second Law of Motion:

$$F=ma$$

Where:

• $F$ is the force applied (20 N),
• $m$ is the mass of the object (5 kg),
• $a$ is the acceleration, which we need to find.

First, let’s rearrange the equation to solve for acceleration:

a=Fm=205=4 m/s2a = \frac{F}{m} = \frac{20}{5} = 4 \, \text{m/s}^2a=mF​=520​=4m/s2

So, the acceleration of the object is 4 m/s24 \, \text{m/s}^24m/s2.

Force Acceleration Calculation: Let’s solve this using Newton’s Second Law of Motion:

$$F=ma$$

Where:

• $F$ is the force applied (20 N),
• $m$ is the mass of the object (5 kg),
• $a$ is the acceleration, which we need to find.

First, let’s rearrange the equation to solve for acceleration:

a=Fm=205=4 m/s2a = \frac{F}{m} = \frac{20}{5} = 4 \, \text{m/s}^2a=mF​=520​=4m/s2

So, the acceleration of the object is 4 m/s24 \, \text{m/s}^24m/s2.

Let’s solve this using Newton’s Second Law of Motion:

$$F=ma$$

Where:

• $F$ is the force applied (20 N),
• $m$ is the mass of the object (5 kg),
• $a$ is the acceleration, which we need to find.

First, let’s rearrange the equation to solve for acceleration:

a=Fm=205=4 m/s2a = \frac{F}{m} = \frac{20}{5} = 4 \, \text{m/s}^2a=mF​=520​=4m/s2

So, the acceleration of the object is 4 m/s24 \, \text{m/s}^24m/s2.